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All functions g:N-->N which have a single-fold Diophantine representation are dominated by a limit-computable function f:N\{0}-->N which is implemented in MuPAD and whose computability is an open problem

机译:所有函数g:N - > N,具有单倍丢番图   表示由极限可计算函数f:N \ {0} - > N控制   在mupaD中实现,其可计算性是一个开放的问题

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摘要

Let E_n={x_k=1, x_i+x_j=x_k, x_i \cdot x_j=x_k: i,j,k \in {1,...,n}}. For anyinteger n \geq 2214, we define a system T \subseteq E_n which has a uniqueinteger solution (a_1,...,a_n). We prove that the numbers a_1,...,a_n arepositive and max(a_1,...,a_n)>2^(2^n). For a positive integer n, let f(n)denote the smallest non-negative integer b such that for each system S\subseteq E_n with a unique solution in non-negative integers x_1,...,x_n, thissolution belongs to [0,b]^n. We prove that if a function g:N-->N has asingle-fold Diophantine representation, then f dominates g. We present a MuPADcode which takes as input a positive integer n, performs an infinite loop,returns a non-negative integer on each iteration, and returns f(n) on eachsufficiently high iteration.
机译:令E_n = {x_k = 1,x_i + x_j = x_k,x_i \ cdot x_j = x_k:i,j,k \ in {1,...,n}}。对于任何整数n \ geq 2214,我们定义一个系统T \ subseteq E_n,该系统具有唯一的整数解(a_1,...,a_n)。我们证明数字a_1,...,a_n是正数并且max(a_1,...,a_n)> 2 ^(2 ^ n)。对于正整数n,令f(n)表示最小的非负整数b,使得对于每个系统S \ subseteq E_n,在非负整数x_1,...,x_n中具有唯一解,该解决方案属于[0 ,b] ^ n。我们证明,如果函数g:N-> N具有单倍Diophantine表示,则f支配g。我们提供了一个MuPADcode,它以正整数n作为输入,执行无限循环,在每次迭代中返回非负整数,并在每次足够高的迭代中返回f(n)。

著录项

  • 作者

    Tyszka, Apoloniusz;

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  • 年度 2015
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  • 原文格式 PDF
  • 正文语种 {"code":"en","name":"English","id":9}
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